5(3-y)=2(y+4)

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Solution for 5(3-y)=2(y+4) equation: 



5(3-y)=2(y+4)

We move all terms to the left:

5(3-y)-(2(y+4))=0

We add all the numbers together, and all the variables

5(-1y+3)-(2(y+4))=0

We multiply parentheses

-5y-(2(y+4))+15=0



We calculate terms in parentheses: -(2(y+4)), so:

2(y+4)

We multiply parentheses

2y+8

Back to the equation:

-(2y+8)



We get rid of parentheses

-5y-2y-8+15=0

We add all the numbers together, and all the variables

-7y+7=0

We move all terms containing y to the left, all other terms to the right

-7y=-7

y=-7/-7

y=1

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