5(3-x)=-10(x+2)

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Solution for 5(3-x)=-10(x+2) equation: 



5(3-x)=-10(x+2)

We move all terms to the left:

5(3-x)-(-10(x+2))=0

We add all the numbers together, and all the variables

5(-1x+3)-(-10(x+2))=0

We multiply parentheses

-5x-(-10(x+2))+15=0



We calculate terms in parentheses: -(-10(x+2)), so:

-10(x+2)

We multiply parentheses

-10x-20

Back to the equation:

-(-10x-20)



We get rid of parentheses

-5x+10x+20+15=0

We add all the numbers together, and all the variables

5x+35=0

We move all terms containing x to the left, all other terms to the right

5x=-35

x=-35/5

x=-7

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