5(3-2x)=6-2(x-4)

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Solution for 5(3-2x)=6-2(x-4) equation: 



5(3-2x)=6-2(x-4)

We move all terms to the left:

5(3-2x)-(6-2(x-4))=0

We add all the numbers together, and all the variables

5(-2x+3)-(6-2(x-4))=0

We multiply parentheses

-10x-(6-2(x-4))+15=0



We calculate terms in parentheses: -(6-2(x-4)), so:

6-2(x-4)

determiningTheFunctionDomain
-2(x-4)+6

We multiply parentheses

-2x+8+6

We add all the numbers together, and all the variables

-2x+14

Back to the equation:

-(-2x+14)



We get rid of parentheses

-10x+2x-14+15=0

We add all the numbers together, and all the variables

-8x+1=0

We move all terms containing x to the left, all other terms to the right

-8x=-1

x=-1/-8

x=1/8

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