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5(3-2x)=3(4x-5)
We move all terms to the left:
5(3-2x)-(3(4x-5))=0
We add all the numbers together, and all the variables
5(-2x+3)-(3(4x-5))=0
We multiply parentheses
-10x-(3(4x-5))+15=0
We calculate terms in parentheses: -(3(4x-5)), so:We get rid of parentheses
3(4x-5)
We multiply parentheses
12x-15
Back to the equation:
-(12x-15)
-10x-12x+15+15=0
We add all the numbers together, and all the variables
-22x+30=0
We move all terms containing x to the left, all other terms to the right
-22x=-30
x=-30/-22
x=1+4/11
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