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5(3-2x)=-(10+10x)
We move all terms to the left:
5(3-2x)-(-(10+10x))=0
We add all the numbers together, and all the variables
5(-2x+3)-(-(10x+10))=0
We multiply parentheses
-10x-(-(10x+10))+15=0
We calculate terms in parentheses: -(-(10x+10)), so:We get rid of parentheses
-(10x+10)
We get rid of parentheses
-10x-10
Back to the equation:
-(-10x-10)
-10x+10x+10+15=0
We add all the numbers together, and all the variables
25!=0
There is no solution for this equation
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