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5(3-(2-7x))+x=4(9x+2)-3
We move all terms to the left:
5(3-(2-7x))+x-(4(9x+2)-3)=0
We add all the numbers together, and all the variables
5(3-(-7x+2))+x-(4(9x+2)-3)=0
We add all the numbers together, and all the variables
x+5(3-(-7x+2))-(4(9x+2)-3)=0
We calculate terms in parentheses: -(4(9x+2)-3), so:We get rid of parentheses
4(9x+2)-3
We multiply parentheses
36x+8-3
We add all the numbers together, and all the variables
36x+5
Back to the equation:
-(36x+5)
x+5(3-(-7x+2))-36x-5=0
We add all the numbers together, and all the variables
-35x+5(3-(-7x+2))-5=0
We move all terms containing x to the left, all other terms to the right
-35x+5(3-(-7x+2))=5
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