5(2z-1)=-(-3z-21)

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Solution for 5(2z-1)=-(-3z-21) equation: 



5(2z-1)=-(-3z-21)

We move all terms to the left:

5(2z-1)-(-(-3z-21))=0

We multiply parentheses

10z-(-(-3z-21))-5=0



We calculate terms in parentheses: -(-(-3z-21)), so:

-(-3z-21)

We get rid of parentheses

3z+21

Back to the equation:

-(3z+21)



We get rid of parentheses

10z-3z-21-5=0

We add all the numbers together, and all the variables

7z-26=0

We move all terms containing z to the left, all other terms to the right

7z=26

z=26/7

z=3+5/7

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