5(2z-1)-4(z+5)=4(z+1)

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Solution for 5(2z-1)-4(z+5)=4(z+1) equation:


5(2z-1)-4(z+5)=4(z+1)

We simplify the equation to the form, which is simple to understand
5(2z-1)-4(z+5)=4(z+1)

Reorder the terms in parentheses
+(+10z-5)-4*(z+5)=4*(z+1)

Remove unnecessary parentheses
+10z-5-4+*(+z+5+)=+4+*(+z+1+)

Reorder the terms in parentheses
+10z-5+(-4z-20)=4*(z+1)

Remove unnecessary parentheses
+10z-5-4z-20=+4+*(+z+1+)

Reorder the terms in parentheses
+10z-5-4z-20=+(+4z+4)

Remove unnecessary parentheses
+10z-5-4z-20=+4z+4

We move all terms containing z to the left and all other terms to the right.
+10z-4z-4z=+4+5+20

We simplify left and right side of the equation.
+2z=+29

We divide both sides of the equation by 2 to get z.
z=14.5

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