5(2z-1)-4(2+3)=4(z+1)

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Solution for 5(2z-1)-4(2+3)=4(z+1) equation:


Simplifying
5(2z + -1) + -4(2 + 3) = 4(z + 1)

Reorder the terms:
5(-1 + 2z) + -4(2 + 3) = 4(z + 1)
(-1 * 5 + 2z * 5) + -4(2 + 3) = 4(z + 1)
(-5 + 10z) + -4(2 + 3) = 4(z + 1)

Combine like terms: 2 + 3 = 5
-5 + 10z + -4(5) = 4(z + 1)

Multiply -4 * 5
-5 + 10z + -20 = 4(z + 1)

Reorder the terms:
-5 + -20 + 10z = 4(z + 1)

Combine like terms: -5 + -20 = -25
-25 + 10z = 4(z + 1)

Reorder the terms:
-25 + 10z = 4(1 + z)
-25 + 10z = (1 * 4 + z * 4)
-25 + 10z = (4 + 4z)

Solving
-25 + 10z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-25 + 10z + -4z = 4 + 4z + -4z

Combine like terms: 10z + -4z = 6z
-25 + 6z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-25 + 6z = 4 + 0
-25 + 6z = 4

Add '25' to each side of the equation.
-25 + 25 + 6z = 4 + 25

Combine like terms: -25 + 25 = 0
0 + 6z = 4 + 25
6z = 4 + 25

Combine like terms: 4 + 25 = 29
6z = 29

Divide each side by '6'.
z = 4.833333333

Simplifying
z = 4.833333333

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