5(2z+1)=3(z+4)-5

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Solution for 5(2z+1)=3(z+4)-5 equation: 



5(2z+1)=3(z+4)-5

We move all terms to the left:

5(2z+1)-(3(z+4)-5)=0

We multiply parentheses

10z-(3(z+4)-5)+5=0



We calculate terms in parentheses: -(3(z+4)-5), so:

3(z+4)-5

We multiply parentheses

3z+12-5

We add all the numbers together, and all the variables

3z+7

Back to the equation:

-(3z+7)



We get rid of parentheses

10z-3z-7+5=0

We add all the numbers together, and all the variables

7z-2=0

We move all terms containing z to the left, all other terms to the right

7z=2

z=2/7

z=2/7

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