5(2z+1)-7=68

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Solution for 5(2z+1)-7=68 equation: 



5(2z+1)-7=68

We move all terms to the left:

5(2z+1)-7-(68)=0

We add all the numbers together, and all the variables

5(2z+1)-75=0

We multiply parentheses

10z+5-75=0

We add all the numbers together, and all the variables

10z-70=0

We move all terms containing z to the left, all other terms to the right

10z=70

z=70/10

z=7

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