5(2y-3)=3(2y+3)y=5

Solution for 5(2y-3)=3(2y+3)y=5 equation:

5(2y-3)=3(2y+3)y=5

We move all terms to the left:

5(2y-3)-(3(2y+3)y)=0

We multiply parentheses

10y-(3(2y+3)y)-15=0


We calculate terms in parentheses: -(3(2y+3)y), so:

3(2y+3)y

We multiply parentheses

6y^2+9y

Back to the equation:

-(6y^2+9y)


We get rid of parentheses

-6y^2+10y-9y-15=0

We add all the numbers together, and all the variables

-6y^2+y-15=0

a = -6; b = 1; c = -15;
Δ = b2-4ac
Δ = 12-4·(-6)·(-15)
Δ = -359
Delta is less than zero, so there is no solution for the equation