5(2y-3)-6=6(4y+1)+7

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Solution for 5(2y-3)-6=6(4y+1)+7 equation: 



5(2y-3)-6=6(4y+1)+7

We move all terms to the left:

5(2y-3)-6-(6(4y+1)+7)=0

We multiply parentheses

10y-(6(4y+1)+7)-15-6=0



We calculate terms in parentheses: -(6(4y+1)+7), so:

6(4y+1)+7

We multiply parentheses

24y+6+7

We add all the numbers together, and all the variables

24y+13

Back to the equation:

-(24y+13)



We add all the numbers together, and all the variables

10y-(24y+13)-21=0

We get rid of parentheses

10y-24y-13-21=0

We add all the numbers together, and all the variables

-14y-34=0

We move all terms containing y to the left, all other terms to the right

-14y=34

y=34/-14

y=-2+3/7

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