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5(2y-3)-4=8-2y-15
We move all terms to the left:
5(2y-3)-4-(8-2y-15)=0
We add all the numbers together, and all the variables
5(2y-3)-(-2y-7)-4=0
We multiply parentheses
10y-(-2y-7)-15-4=0
We get rid of parentheses
10y+2y+7-15-4=0
We add all the numbers together, and all the variables
12y-12=0
We move all terms containing y to the left, all other terms to the right
12y=12
y=12/12
y=1
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