5(2y-3)-1=4(6+2y)

Solution for 5(2y-3)-1=4(6+2y) equation:

5(2y-3)-1=4(6+2y)

We move all terms to the left:

5(2y-3)-1-(4(6+2y))=0

We add all the numbers together, and all the variables

5(2y-3)-(4(2y+6))-1=0

We multiply parentheses

10y-(4(2y+6))-15-1=0


We calculate terms in parentheses: -(4(2y+6)), so:

4(2y+6)

We multiply parentheses

8y+24

Back to the equation:

-(8y+24)


We add all the numbers together, and all the variables

10y-(8y+24)-16=0

We get rid of parentheses

10y-8y-24-16=0

We add all the numbers together, and all the variables

2y-40=0

We move all terms containing y to the left, all other terms to the right

2y=40

y=40/2

y=20