5(2y-1)+4y=23

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Solution for 5(2y-1)+4y=23 equation: 



5(2y-1)+4y=23

We move all terms to the left:

5(2y-1)+4y-(23)=0

We add all the numbers together, and all the variables

4y+5(2y-1)-23=0

We multiply parentheses

4y+10y-5-23=0

We add all the numbers together, and all the variables

14y-28=0

We move all terms containing y to the left, all other terms to the right

14y=28

y=28/14

y=2

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