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5(2y+4)=2(3y+2)
We move all terms to the left:
5(2y+4)-(2(3y+2))=0
We multiply parentheses
10y-(2(3y+2))+20=0
We calculate terms in parentheses: -(2(3y+2)), so:We get rid of parentheses
2(3y+2)
We multiply parentheses
6y+4
Back to the equation:
-(6y+4)
10y-6y-4+20=0
We add all the numbers together, and all the variables
4y+16=0
We move all terms containing y to the left, all other terms to the right
4y=-16
y=-16/4
y=-4
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