5(2y+3)=8+4y+7+6y

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Solution for 5(2y+3)=8+4y+7+6y equation: 



5(2y+3)=8+4y+7+6y

We move all terms to the left:

5(2y+3)-(8+4y+7+6y)=0

We add all the numbers together, and all the variables

5(2y+3)-(10y+15)=0

We multiply parentheses

10y-(10y+15)+15=0

We get rid of parentheses

10y-10y-15+15=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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