5(2y+3)=2(3y-2)

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Solution for 5(2y+3)=2(3y-2) equation: 



5(2y+3)=2(3y-2)

We move all terms to the left:

5(2y+3)-(2(3y-2))=0

We multiply parentheses

10y-(2(3y-2))+15=0



We calculate terms in parentheses: -(2(3y-2)), so:

2(3y-2)

We multiply parentheses

6y-4

Back to the equation:

-(6y-4)



We get rid of parentheses

10y-6y+4+15=0

We add all the numbers together, and all the variables

4y+19=0

We move all terms containing y to the left, all other terms to the right

4y=-19

y=-19/4

y=-4+3/4

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