5(2y+3)-3=(4y-4)-14

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Solution for 5(2y+3)-3=(4y-4)-14 equation: 



5(2y+3)-3=(4y-4)-14

We move all terms to the left:

5(2y+3)-3-((4y-4)-14)=0

We multiply parentheses

10y-((4y-4)-14)+15-3=0



We calculate terms in parentheses: -((4y-4)-14), so:

(4y-4)-14

We get rid of parentheses

4y-4-14

We add all the numbers together, and all the variables

4y-18

Back to the equation:

-(4y-18)



We add all the numbers together, and all the variables

10y-(4y-18)+12=0

We get rid of parentheses

10y-4y+18+12=0

We add all the numbers together, and all the variables

6y+30=0

We move all terms containing y to the left, all other terms to the right

6y=-30

y=-30/6

y=-5

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