5(2x-8)=10(x-4)

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Solution for 5(2x-8)=10(x-4) equation:


Simplifying
5(2x + -8) = 10(x + -4)

Reorder the terms:
5(-8 + 2x) = 10(x + -4)
(-8 * 5 + 2x * 5) = 10(x + -4)
(-40 + 10x) = 10(x + -4)

Reorder the terms:
-40 + 10x = 10(-4 + x)
-40 + 10x = (-4 * 10 + x * 10)
-40 + 10x = (-40 + 10x)

Add '40' to each side of the equation.
-40 + 40 + 10x = -40 + 40 + 10x

Combine like terms: -40 + 40 = 0
0 + 10x = -40 + 40 + 10x
10x = -40 + 40 + 10x

Combine like terms: -40 + 40 = 0
10x = 0 + 10x
10x = 10x

Add '-10x' to each side of the equation.
10x + -10x = 10x + -10x

Combine like terms: 10x + -10x = 0
0 = 10x + -10x

Combine like terms: 10x + -10x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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