5(2x-8)-4=5(x-3)+(1)

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Solution for 5(2x-8)-4=5(x-3)+(1) equation:



5(2x-8)-4=5(x-3)+(1)
We move all terms to the left:
5(2x-8)-4-(5(x-3)+(1))=0
We multiply parentheses
10x-(5(x-3)+1)-40-4=0
We calculate terms in parentheses: -(5(x-3)+1), so:
5(x-3)+1
We multiply parentheses
5x-15+1
We add all the numbers together, and all the variables
5x-14
Back to the equation:
-(5x-14)
We add all the numbers together, and all the variables
10x-(5x-14)-44=0
We get rid of parentheses
10x-5x+14-44=0
We add all the numbers together, and all the variables
5x-30=0
We move all terms containing x to the left, all other terms to the right
5x=30
x=30/5
x=6

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