5(2x-8)+4x=-20+2(-10-3x)

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Solution for 5(2x-8)+4x=-20+2(-10-3x) equation: 



5(2x-8)+4x=-20+2(-10-3x)

We move all terms to the left:

5(2x-8)+4x-(-20+2(-10-3x))=0

We add all the numbers together, and all the variables

5(2x-8)+4x-(-20+2(-3x-10))=0

We add all the numbers together, and all the variables

4x+5(2x-8)-(-20+2(-3x-10))=0

We multiply parentheses

4x+10x-(-20+2(-3x-10))-40=0



We calculate terms in parentheses: -(-20+2(-3x-10)), so:

-20+2(-3x-10)

determiningTheFunctionDomain
2(-3x-10)-20

We multiply parentheses

-6x-20-20

We add all the numbers together, and all the variables

-6x-40

Back to the equation:

-(-6x-40)



We add all the numbers together, and all the variables

14x-(-6x-40)-40=0

We get rid of parentheses

14x+6x+40-40=0

We add all the numbers together, and all the variables

20x=0

x=0/20

x=0

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