5(2x-7)-3(3x-8)=9x-162(3x-5)-13

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Solution for 5(2x-7)-3(3x-8)=9x-162(3x-5)-13 equation: 



5(2x-7)-3(3x-8)=9x-162(3x-5)-13

We move all terms to the left:

5(2x-7)-3(3x-8)-(9x-162(3x-5)-13)=0

We multiply parentheses

10x-9x-(9x-162(3x-5)-13)-35+24=0



We calculate terms in parentheses: -(9x-162(3x-5)-13), so:

9x-162(3x-5)-13

We multiply parentheses

9x-486x+810-13

We add all the numbers together, and all the variables

-477x+797

Back to the equation:

-(-477x+797)



We add all the numbers together, and all the variables

x-(-477x+797)-11=0

We get rid of parentheses

x+477x-797-11=0

We add all the numbers together, and all the variables

478x-808=0

We move all terms containing x to the left, all other terms to the right

478x=808

x=808/478

x=1+165/239

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