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5(2x-5)-4x=3x+2(x-5)
We move all terms to the left:
5(2x-5)-4x-(3x+2(x-5))=0
We add all the numbers together, and all the variables
-4x+5(2x-5)-(3x+2(x-5))=0
We multiply parentheses
-4x+10x-(3x+2(x-5))-25=0
We calculate terms in parentheses: -(3x+2(x-5)), so:We add all the numbers together, and all the variables
3x+2(x-5)
We multiply parentheses
3x+2x-10
We add all the numbers together, and all the variables
5x-10
Back to the equation:
-(5x-10)
6x-(5x-10)-25=0
We get rid of parentheses
6x-5x+10-25=0
We add all the numbers together, and all the variables
x-15=0
We move all terms containing x to the left, all other terms to the right
x=15
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