5(2x-5)-4=5(x-4)+36

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Solution for 5(2x-5)-4=5(x-4)+36 equation: 



5(2x-5)-4=5(x-4)+36

We move all terms to the left:

5(2x-5)-4-(5(x-4)+36)=0

We multiply parentheses

10x-(5(x-4)+36)-25-4=0



We calculate terms in parentheses: -(5(x-4)+36), so:

5(x-4)+36

We multiply parentheses

5x-20+36

We add all the numbers together, and all the variables

5x+16

Back to the equation:

-(5x+16)



We add all the numbers together, and all the variables

10x-(5x+16)-29=0

We get rid of parentheses

10x-5x-16-29=0

We add all the numbers together, and all the variables

5x-45=0

We move all terms containing x to the left, all other terms to the right

5x=45

x=45/5

x=9

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