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5(2x-4)=9(x+5)
We move all terms to the left:
5(2x-4)-(9(x+5))=0
We multiply parentheses
10x-(9(x+5))-20=0
We calculate terms in parentheses: -(9(x+5)), so:We get rid of parentheses
9(x+5)
We multiply parentheses
9x+45
Back to the equation:
-(9x+45)
10x-9x-45-20=0
We add all the numbers together, and all the variables
x-65=0
We move all terms containing x to the left, all other terms to the right
x=65
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