5(2x-4)-7(8x+3)=32

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Solution for 5(2x-4)-7(8x+3)=32 equation: 



5(2x-4)-7(8x+3)=32

We move all terms to the left:

5(2x-4)-7(8x+3)-(32)=0

We multiply parentheses

10x-56x-20-21-32=0

We add all the numbers together, and all the variables

-46x-73=0

We move all terms containing x to the left, all other terms to the right

-46x=73

x=73/-46

x=-1+27/46

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