5(2x-3)=7(x+1)

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Solution for 5(2x-3)=7(x+1) equation: 



5(2x-3)=7(x+1)

We move all terms to the left:

5(2x-3)-(7(x+1))=0

We multiply parentheses

10x-(7(x+1))-15=0



We calculate terms in parentheses: -(7(x+1)), so:

7(x+1)

We multiply parentheses

7x+7

Back to the equation:

-(7x+7)



We get rid of parentheses

10x-7x-7-15=0

We add all the numbers together, and all the variables

3x-22=0

We move all terms containing x to the left, all other terms to the right

3x=22

x=22/3

x=7+1/3

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