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5(2x-3)=4(x-3)
We move all terms to the left:
5(2x-3)-(4(x-3))=0
We multiply parentheses
10x-(4(x-3))-15=0
We calculate terms in parentheses: -(4(x-3)), so:We get rid of parentheses
4(x-3)
We multiply parentheses
4x-12
Back to the equation:
-(4x-12)
10x-4x+12-15=0
We add all the numbers together, and all the variables
6x-3=0
We move all terms containing x to the left, all other terms to the right
6x=3
x=3/6
x=1/2
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