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5(2x-3)=3(3x-7)=5
We move all terms to the left:
5(2x-3)-(3(3x-7))=0
We multiply parentheses
10x-(3(3x-7))-15=0
We calculate terms in parentheses: -(3(3x-7)), so:We get rid of parentheses
3(3x-7)
We multiply parentheses
9x-21
Back to the equation:
-(9x-21)
10x-9x+21-15=0
We add all the numbers together, and all the variables
x+6=0
We move all terms containing x to the left, all other terms to the right
x=-6
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