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5(2x-3)=2(x+2)+2(2x-1)-7
We move all terms to the left:
5(2x-3)-(2(x+2)+2(2x-1)-7)=0
We multiply parentheses
10x-(2(x+2)+2(2x-1)-7)-15=0
We calculate terms in parentheses: -(2(x+2)+2(2x-1)-7), so:We get rid of parentheses
2(x+2)+2(2x-1)-7
We multiply parentheses
2x+4x+4-2-7
We add all the numbers together, and all the variables
6x-5
Back to the equation:
-(6x-5)
10x-6x+5-15=0
We add all the numbers together, and all the variables
4x-10=0
We move all terms containing x to the left, all other terms to the right
4x=10
x=10/4
x=2+1/2
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