5(2x-3)=10(x-2)+5

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Solution for 5(2x-3)=10(x-2)+5 equation: 



5(2x-3)=10(x-2)+5

We move all terms to the left:

5(2x-3)-(10(x-2)+5)=0

We multiply parentheses

10x-(10(x-2)+5)-15=0



We calculate terms in parentheses: -(10(x-2)+5), so:

10(x-2)+5

We multiply parentheses

10x-20+5

We add all the numbers together, and all the variables

10x-15

Back to the equation:

-(10x-15)



We get rid of parentheses

10x-10x+15-15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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