If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5(2x-3)=(18-27x)/9
We move all terms to the left:
5(2x-3)-((18-27x)/9)=0
We add all the numbers together, and all the variables
5(2x-3)-((-27x+18)/9)=0
We multiply parentheses
10x-((-27x+18)/9)-15=0
We multiply all the terms by the denominator
10x*9)-((-27x+18)-15*9)=0
We add all the numbers together, and all the variables
10x*9)-((-27x+18)=0
Wy multiply elements
90x^2=0
a = 90; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·90·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{180}=0$
| 16^2x-3=8^x | | 4/5u+7/25=1/5 | | -7x+8+2x=-9x+6+3x | | -3/8+v=1/4 | | x=2x^2+x-7/2x+8 | | ŷ=-210+5.6x | | 4*a+5=2+3.25*a | | (5x+7x)+3x=70 | | x–5=12 | | 10x-15=12-5x | | 32-4t=3t+9 | | 8−–y=15 | | 0.3(80p+25)=151.5 | | 8+–4m=12 | | /10(b+4)=4(15) | | /49-2a+16+3a=105 | | 144+2x=130 | | 8c-17+4c-3=4 | | 2y+2y+30=180 | | X^2+10=3x17 | | 6x+89=143 | | (X-2)/(x-3)=3/2 | | 19=a-4* | | 10x+5=3(5x-1)+5 | | 9.67-0.4q=-9.28-10q-7.93 | | 15.3+1f=1.3-1f | | 3.2c-1=5 | | -8n-10-n=8-7n | | 8/3*(c)-2=2/3*(c)-12 | | 8x-1+7x+6=180 | | 45-2.50c=780 | | 3x-12+9=72 |