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5(2x-3)-7=3(x+2)
We move all terms to the left:
5(2x-3)-7-(3(x+2))=0
We multiply parentheses
10x-(3(x+2))-15-7=0
We calculate terms in parentheses: -(3(x+2)), so:We add all the numbers together, and all the variables
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
10x-(3x+6)-22=0
We get rid of parentheses
10x-3x-6-22=0
We add all the numbers together, and all the variables
7x-28=0
We move all terms containing x to the left, all other terms to the right
7x=28
x=28/7
x=4
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