5(2x-3)-4(5x-7)=19-2(x+11)

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Solution for 5(2x-3)-4(5x-7)=19-2(x+11) equation: 



5(2x-3)-4(5x-7)=19-2(x+11)

We move all terms to the left:

5(2x-3)-4(5x-7)-(19-2(x+11))=0

We multiply parentheses

10x-20x-(19-2(x+11))-15+28=0



We calculate terms in parentheses: -(19-2(x+11)), so:

19-2(x+11)

determiningTheFunctionDomain
-2(x+11)+19

We multiply parentheses

-2x-22+19

We add all the numbers together, and all the variables

-2x-3

Back to the equation:

-(-2x-3)



We add all the numbers together, and all the variables

-10x-(-2x-3)+13=0

We get rid of parentheses

-10x+2x+3+13=0

We add all the numbers together, and all the variables

-8x+16=0

We move all terms containing x to the left, all other terms to the right

-8x=-16

x=-16/-8

x=+2

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