5(2x-3)-3(x-1)=-2(x-4)+x+2

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Solution for 5(2x-3)-3(x-1)=-2(x-4)+x+2 equation: 



5(2x-3)-3(x-1)=-2(x-4)+x+2

We move all terms to the left:

5(2x-3)-3(x-1)-(-2(x-4)+x+2)=0

We multiply parentheses

10x-3x-(-2(x-4)+x+2)-15+3=0



We calculate terms in parentheses: -(-2(x-4)+x+2), so:

-2(x-4)+x+2

We add all the numbers together, and all the variables

x-2(x-4)+2

We multiply parentheses

x-2x+8+2

We add all the numbers together, and all the variables

-1x+10

Back to the equation:

-(-1x+10)



We add all the numbers together, and all the variables

7x-(-1x+10)-12=0

We get rid of parentheses

7x+1x-10-12=0

We add all the numbers together, and all the variables

8x-22=0

We move all terms containing x to the left, all other terms to the right

8x=22

x=22/8

x=2+3/4

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