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5(2x-3)-2=5(x-5)+33
We move all terms to the left:
5(2x-3)-2-(5(x-5)+33)=0
We multiply parentheses
10x-(5(x-5)+33)-15-2=0
We calculate terms in parentheses: -(5(x-5)+33), so:We add all the numbers together, and all the variables
5(x-5)+33
We multiply parentheses
5x-25+33
We add all the numbers together, and all the variables
5x+8
Back to the equation:
-(5x+8)
10x-(5x+8)-17=0
We get rid of parentheses
10x-5x-8-17=0
We add all the numbers together, and all the variables
5x-25=0
We move all terms containing x to the left, all other terms to the right
5x=25
x=25/5
x=5
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