5(2x-3)+7=12-5(x-1)

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Solution for 5(2x-3)+7=12-5(x-1) equation: 



5(2x-3)+7=12-5(x-1)

We move all terms to the left:

5(2x-3)+7-(12-5(x-1))=0

We multiply parentheses

10x-(12-5(x-1))-15+7=0



We calculate terms in parentheses: -(12-5(x-1)), so:

12-5(x-1)

determiningTheFunctionDomain
-5(x-1)+12

We multiply parentheses

-5x+5+12

We add all the numbers together, and all the variables

-5x+17

Back to the equation:

-(-5x+17)



We add all the numbers together, and all the variables

10x-(-5x+17)-8=0

We get rid of parentheses

10x+5x-17-8=0

We add all the numbers together, and all the variables

15x-25=0

We move all terms containing x to the left, all other terms to the right

15x=25

x=25/15

x=1+2/3

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