5(2x-3)+4(4x+7)-48=3(2x+1)+4(x+3)+30

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Solution for 5(2x-3)+4(4x+7)-48=3(2x+1)+4(x+3)+30 equation:



5(2x-3)+4(4x+7)-48=3(2x+1)+4(x+3)+30
We move all terms to the left:
5(2x-3)+4(4x+7)-48-(3(2x+1)+4(x+3)+30)=0
We multiply parentheses
10x+16x-(3(2x+1)+4(x+3)+30)-15+28-48=0
We calculate terms in parentheses: -(3(2x+1)+4(x+3)+30), so:
3(2x+1)+4(x+3)+30
We multiply parentheses
6x+4x+3+12+30
We add all the numbers together, and all the variables
10x+45
Back to the equation:
-(10x+45)
We add all the numbers together, and all the variables
26x-(10x+45)-35=0
We get rid of parentheses
26x-10x-45-35=0
We add all the numbers together, and all the variables
16x-80=0
We move all terms containing x to the left, all other terms to the right
16x=80
x=80/16
x=5

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