5(2x-3)+1+4(3x-5)=3(x+10)+4(2x+8)+x

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Solution for 5(2x-3)+1+4(3x-5)=3(x+10)+4(2x+8)+x equation: 



5(2x-3)+1+4(3x-5)=3(x+10)+4(2x+8)+x

We move all terms to the left:

5(2x-3)+1+4(3x-5)-(3(x+10)+4(2x+8)+x)=0

We multiply parentheses

10x+12x-(3(x+10)+4(2x+8)+x)-15-20+1=0



We calculate terms in parentheses: -(3(x+10)+4(2x+8)+x), so:

3(x+10)+4(2x+8)+x

We add all the numbers together, and all the variables

x+3(x+10)+4(2x+8)

We multiply parentheses

x+3x+8x+30+32

We add all the numbers together, and all the variables

12x+62

Back to the equation:

-(12x+62)



We add all the numbers together, and all the variables

22x-(12x+62)-34=0

We get rid of parentheses

22x-12x-62-34=0

We add all the numbers together, and all the variables

10x-96=0

We move all terms containing x to the left, all other terms to the right

10x=96

x=96/10

x=9+3/5

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