5(2x-2)-4=5(x-3)+31

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Solution for 5(2x-2)-4=5(x-3)+31 equation: 



5(2x-2)-4=5(x-3)+31

We move all terms to the left:

5(2x-2)-4-(5(x-3)+31)=0

We multiply parentheses

10x-(5(x-3)+31)-10-4=0



We calculate terms in parentheses: -(5(x-3)+31), so:

5(x-3)+31

We multiply parentheses

5x-15+31

We add all the numbers together, and all the variables

5x+16

Back to the equation:

-(5x+16)



We add all the numbers together, and all the variables

10x-(5x+16)-14=0

We get rid of parentheses

10x-5x-16-14=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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