5(2x-2)+6(x+7)=7(x+6)-(x+4)

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Solution for 5(2x-2)+6(x+7)=7(x+6)-(x+4) equation: 



5(2x-2)+6(x+7)=7(x+6)-(x+4)

We move all terms to the left:

5(2x-2)+6(x+7)-(7(x+6)-(x+4))=0

We multiply parentheses

10x+6x-(7(x+6)-(x+4))-10+42=0



We calculate terms in parentheses: -(7(x+6)-(x+4)), so:

7(x+6)-(x+4)

We multiply parentheses

7x-(x+4)+42

We get rid of parentheses

7x-x-4+42

We add all the numbers together, and all the variables

6x+38

Back to the equation:

-(6x+38)



We add all the numbers together, and all the variables

16x-(6x+38)+32=0

We get rid of parentheses

16x-6x-38+32=0

We add all the numbers together, and all the variables

10x-6=0

We move all terms containing x to the left, all other terms to the right

10x=6

x=6/10

x=3/5

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