5(2x-2)+4=-8-(-3x-2)

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Solution for 5(2x-2)+4=-8-(-3x-2) equation: 



5(2x-2)+4=-8-(-3x-2)

We move all terms to the left:

5(2x-2)+4-(-8-(-3x-2))=0

We multiply parentheses

10x-(-8-(-3x-2))-10+4=0



We calculate terms in parentheses: -(-8-(-3x-2)), so:

-8-(-3x-2)

determiningTheFunctionDomain
-(-3x-2)-8

We get rid of parentheses

3x+2-8

We add all the numbers together, and all the variables

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

10x-(3x-6)-6=0

We get rid of parentheses

10x-3x+6-6=0

We add all the numbers together, and all the variables

7x=0

x=0/7

x=0

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