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5(2x-1)x=16x
We move all terms to the left:
5(2x-1)x-(16x)=0
We add all the numbers together, and all the variables
-16x+5(2x-1)x=0
We multiply parentheses
10x^2-16x-5x=0
We add all the numbers together, and all the variables
10x^2-21x=0
a = 10; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·10·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*10}=\frac{0}{20} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*10}=\frac{42}{20} =2+1/10 $
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