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5(2x-1)x4(2x-1)-3(2x-1)=4(x+1)
We move all terms to the left:
5(2x-1)x4(2x-1)-3(2x-1)-(4(x+1))=0
We multiply parentheses
5(2x-1)x4(2x-1)-6x-(4(x+1))+3=0
We calculate terms in parentheses: -(4(x+1)), so:We add all the numbers together, and all the variables
4(x+1)
We multiply parentheses
4x+4
Back to the equation:
-(4x+4)
-6x+5(2x-1)x4(2x-1)-(4x+4)+3=0
We get rid of parentheses
-6x+5(2x-1)x4(2x-1)-4x-4+3=0
We add all the numbers together, and all the variables
-10x+5(2x-1)x4(2x-1)-1=0
We move all terms containing x to the left, all other terms to the right
-10x+5(2x-1)x4(2x-1)=1
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