5(2x-1)=9(x+1)-18

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Solution for 5(2x-1)=9(x+1)-18 equation: 



5(2x-1)=9(x+1)-18

We move all terms to the left:

5(2x-1)-(9(x+1)-18)=0

We multiply parentheses

10x-(9(x+1)-18)-5=0



We calculate terms in parentheses: -(9(x+1)-18), so:

9(x+1)-18

We multiply parentheses

9x+9-18

We add all the numbers together, and all the variables

9x-9

Back to the equation:

-(9x-9)



We get rid of parentheses

10x-9x+9-5=0

We add all the numbers together, and all the variables

x+4=0

We move all terms containing x to the left, all other terms to the right

x=-4

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