5(2x-1)=25+3(x+3)

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Solution for 5(2x-1)=25+3(x+3) equation: 



5(2x-1)=25+3(x+3)

We move all terms to the left:

5(2x-1)-(25+3(x+3))=0

We multiply parentheses

10x-(25+3(x+3))-5=0



We calculate terms in parentheses: -(25+3(x+3)), so:

25+3(x+3)

determiningTheFunctionDomain
3(x+3)+25

We multiply parentheses

3x+9+25

We add all the numbers together, and all the variables

3x+34

Back to the equation:

-(3x+34)



We get rid of parentheses

10x-3x-34-5=0

We add all the numbers together, and all the variables

7x-39=0

We move all terms containing x to the left, all other terms to the right

7x=39

x=39/7

x=5+4/7

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