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5(2x-1)/3-x+4/3=2
We move all terms to the left:
5(2x-1)/3-x+4/3-(2)=0
determiningTheFunctionDomain 5(2x-1)/3-x-2+4/3=0
We add all the numbers together, and all the variables
-1x+5(2x-1)/3-2+4/3=0
We multiply all the terms by the denominator
-1x*3+5(2x-1)+4-2*3=0
We add all the numbers together, and all the variables
-1x*3+5(2x-1)-2=0
We multiply parentheses
-1x*3+10x-5-2=0
Wy multiply elements
-3x+10x-5-2=0
We add all the numbers together, and all the variables
7x-7=0
We move all terms containing x to the left, all other terms to the right
7x=7
x=7/7
x=1
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