5(2x-1)+6x=3(7x-3)-1

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Solution for 5(2x-1)+6x=3(7x-3)-1 equation: 



5(2x-1)+6x=3(7x-3)-1

We move all terms to the left:

5(2x-1)+6x-(3(7x-3)-1)=0

We add all the numbers together, and all the variables

6x+5(2x-1)-(3(7x-3)-1)=0

We multiply parentheses

6x+10x-(3(7x-3)-1)-5=0



We calculate terms in parentheses: -(3(7x-3)-1), so:

3(7x-3)-1

We multiply parentheses

21x-9-1

We add all the numbers together, and all the variables

21x-10

Back to the equation:

-(21x-10)



We add all the numbers together, and all the variables

16x-(21x-10)-5=0

We get rid of parentheses

16x-21x+10-5=0

We add all the numbers together, and all the variables

-5x+5=0

We move all terms containing x to the left, all other terms to the right

-5x=-5

x=-5/-5

x=1

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